0=t^2+6t+8

Solution for 0=t^2+6t+8 equation:

0=t^2+6t+8

We move all terms to the left:

0-(t^2+6t+8)=0

We add all the numbers together, and all the variables

-(t^2+6t+8)=0

We get rid of parentheses

-t^2-6t-8=0

We add all the numbers together, and all the variables

-1t^2-6t-8=0

a = -1; b = -6; c = -8;
Δ = b2-4ac
Δ = -62-4·(-1)·(-8)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2}{2*-1}=\frac{4}{-2}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2}{2*-1}=\frac{8}{-2}
=-4
$